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POJ1065/HDOJ1051 Wooden Sticks
阅读量:7118 次
发布时间:2019-06-28

本文共 2804 字,大约阅读时间需要 9 分钟。

                                                                                         Wooden Sticks
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 14809   Accepted: 6081

Description

There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:
(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l <= l' and w <= w'. Otherwise, it will need 1 minute for setup.
You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are ( 9 , 4 ) , ( 2 , 5 ) , ( 1 , 2 ) , ( 5 , 3 ) , and ( 4 , 1 ) , then the minimum setup time should be 2 minutes since there is a sequence of pairs ( 4 , 1 ) , ( 5 , 3 ) , ( 9 , 4 ) , ( 1 , 2 ) , ( 2 , 5 ) .

Input

The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1 <= n <= 5000 , that represents the number of wooden sticks in the test case, and the second line contains 2n positive integers l1 , w1 , l2 , w2 ,..., ln , wn , each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.

Output

The output should contain the minimum setup time in minutes, one per line.

Sample Input

3 5 4 9 5 2 2 1 3 5 1 4 3 2 2 1 1 2 2 3 1 3 2 2 3 1

Sample Output

213

Source

 
 
思路:有一堆棍子,棍子有长度(L)和重量(W)。机器处理第一根棍子花费1秒。如果后一根棍子的长度(L`)和重量(W`)都比前一根的大,则后一根棍子不需要花费时间(L`>=L&&W`>=W)。求怎样处理这一堆棍子,所花费的时间最少。
        本题可以运用贪心策略,首先按照L进行递增排序,如果L相等则按照W递增进行排序(当然也可以把W当做第一关键字,L当做第二关键字)。排序后,从前往后,找出每一根棍子的后继棍子(条件为后一根棍子的L和W都>=前一根的)。最后可以找出都少条这样的链即为所求。
注意:本题表面上看可以依据L*W的递增进行排序,但是,实际上是不行的。反例:(5,2) (4,3) (4,1) (1,3)。如果按照L,W排序为:(1,3),(4,1),(4,3),(5,2)。结果为2。如果按照面积排序为(1,3),(4,1),(5,2),(4,3)。结果为3。
  
1 #include 
2 #include
3 #include
4 #include
5 #include
6 #include
7 #include
8 #define MAXINT 99999999 9 10 #define MININT -1 11 12 using namespace std; 13 14 struct Node{ 15 int l; 16 int w; 17 }node[5000+4]; 18 19 20 int vis[5000+4]; 21 22 23 24 bool cmp(Node x,Node y) 25 { if(x.l
=node[pre].w) 81 {vis[j]=1;pre=j;} 82 } 83 84 } 85 } 86 87 cout<
<

 

转载于:https://www.cnblogs.com/zjushuiping/archive/2012/08/08/2628928.html

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